450g water at 40^@Cwas kept a calorimeter of water equivalent 50g . 25 g ice at 0^@C is added and simultaneously 5g steam at 100^@Cwas passed to the calorimeter. The final temperature of the calorimeter will be (L_("ice")=80 "cal/g" ,L_("steam")=540cal//g)

450g water at 40^@Cwas kept a calorimeter of water equivalent 50g . 25

1.	450g water at 40^@Cwas kept a calorimeter of water equivalent 50g . 25 g ice at 0^@C is added and simultaneously 5g steam at 100^@Cwas passed to the calorimeter. The final temperature of the calorimeter will be (L_("ice")=80 "cal/g" ,L_("steam")=540cal//g)
Answer» `0^@C` `100^@C` `40^@C` None of these Answer :C