46. Given that the mass of electron is 9.1 * 10% and velocity of electron is 2.2 * 109 msf touncertainity in its velocity is 0.1%, thauncertainity in position would be:(1) 26 nm(2) 32 mm(3) 48 nm(4) 50 nm47

46. Given that the mass of electron is 9.1 * 10% and velocity of ele

1.	46. Given that the mass of electron is 9.1 * 10% and velocity of electron is 2.2 * 109 msf touncertainity in its velocity is 0.1%, thauncertainity in position would be:(1) 26 nm(2) 32 mm(3) 48 nm(4) 50 nm47
Answer» that[begin{array}{l}text { What } Delta x cdot Delta p geq frac{h}{4 pi}begin{aligned}text { Also, } p=& m v RIGHTARROW Delta p=m Delta vRightarrow Delta x cdot(m Delta v) geq frac{h}{4 pi} & frac{h}{4 pi m}END{aligned}end{array}]Criven that ( V=2.2 times 10^{6} mathrm{MLS} ) and ( frac{Delta V}{V}=0,1 % )[Rightarrow Delta V=frac{0.1}{100} times 2.2 times 10^{6} mathrm{mls}=2.2 times 10^{3} mathrm{m} / mathrm{s}][begin{aligned}Rightarrow Delta x=frac{h}{U pi m Delta V} &=frac{6.626 times 10^{-34}}{4 times x times 9.1 times 10^{-31} times 22 times 10^{3}}=&=2.6 times 10^{-8} mathrm{m}=26 mathrm{nm}end{aligned}]