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48. A heating coil of resistance 102 takes a current of 2 Ampere. The heat developed by itin 5 seconds isA. 1000 JoulesB.200 JoulesC.100 JoulesD. 2200 Joules​

Answer»

ANSWER:

CORRECT OPTION is

A

15000

Heat, H=I2Rt=52×20×30

                             =15000



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