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49)The range of the function f(x)=f(x)=\frac{1-\tan x}{1+\tan x}R-\{0\} \text { 2) } R |
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Answer» let f(x) = -1so 1 - tanx-------------- = -1 1 + tan(x)1-tanx = -1 -tan(x)2 = 0an absurd resultso(3) option is correct |
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