4cm high object is placed at a distance of 12cm from a converging lens

4cm high object is placed at a distance of 12cm from a converging lens of focal length of 8cm. Determine the position, size and type of the image.

Answer»

Required ANSWER :-

_____________________________

To FIND :-

___________________________________________

$\frac{1}{f} = \frac{1}{u} + \frac{1}{v} \\ \\ \frac{1}{8} = \frac{1}{12} + \frac{1}{v} \\ \\ \frac{1}{v} = \frac{1}{ - 24} - \frac{1}{ - 12} \\ \\ v = 24cm$