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4z2 – 8z + 3=? A. (2z – 1) (2z – 3) B. (2z + 1) (3 – 2z) C. (2z + 3) (3z + 1) D. (z – 1) (4z – 3) |
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Answer» 4z2 – 8z + 3 Factorizing the equation and taking 2z and – 1 as common, = 4z2 – 6z – 2z + 3 = 2z(2z – 3) – 1(2z – 3) = (2z – 1)(2z – 3). |
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