1.

5. 13 A127is a stable isotope; then, 13 A129 is expected to disintegrate by:a) a - emissionb) B - emissionc) Positron emissiond) Proton emission​

Answer»

Answer:

. 13 A127

is a STABLE ISOTOPE; then, 13 A129 is EXPECTED to DISINTEGRATE by B-emission



Discussion

No Comment Found

Related InterviewSolutions