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1. |
√5-3i = |
Answer» Dekh simple hai. Let inverse multiplicity of root 5-3i = 1/root5-3i.1/root5-3i=root5+3i/root5+3i.Root5+3i/square of root5-square of 3i = root5+3i/5+9 then root5/14+3i/14.Value of i^2=-1. | |