5.6.When 0.15kg of ice at O'C mixed with 0.30 1kg of water at 50°C in

1.	5.6.When 0.15kg of ice at O'C mixed with 0.30 1kg of water at 50°C in a container, theresulting temperature is 6.7°C. Calculate the latent heat of fusion of ice. Given, S of water =41863 kg 'K-.1 guys please give me some thanks.
Answer» Answer: Heat lost by WATER = mSw (θf - θi)w = (0.30 kg) (4186 J kg-1°C-1) x (50.0°C - 6.7°C) = 54376.14 J Heat to melt ice = m2Lf = (0.15 kg)Lf Heat to raise temperature of ice water to FINAL temperature = m1Sw (θf - θi) = (0.15 kg) (4188 J kg-1°C-1) (6.7°C - 0°C) = 4206.93 J Heat lost = Heat gained 54.76.14 J = (0.15 kg) Lf + 4206.93 J ∴ Lf = 3.34 x 105 Jkg-1.Read more on Sarthaks.com - https://www.sarthaks.com/562994/when-of-ice-of-0c-mixed-with-30-kg-water-at-50c-in-container-the-resulting-temperature-7c HOPE THIS HELPED U THANK U MARK ME BRAINLY PLSS

5.6.When 0.15kg of ice at O'C mixed with 0.30 1kg of water at 50°C in a container, theresulting temperature is 6.7°C. Calculate the latent heat of fusion of ice. Given, S of water =41863 kg 'K-.1 guys please give me some thanks.

Answer»

Answer:

Heat lost by WATER = mSw (θf - θi)w = (0.30 kg) (4186 J kg-1°C-1) x (50.0°C - 6.7°C) = 54376.14 J Heat to melt ice = m2Lf = (0.15 kg)Lf Heat to raise temperature of ice water to FINAL temperature = m1Sw (θf - θi) = (0.15 kg) (4188 J kg-1°C-1) (6.7°C - 0°C) = 4206.93 J Heat lost = Heat gained 54.76.14 J = (0.15 kg) Lf + 4206.93 J ∴ Lf = 3.34 x 105 Jkg-1.Read more on Sarthaks.com - https://www.sarthaks.com/562994/when-of-ice-of-0c-mixed-with-30-kg-water-at-50c-in-container-the-resulting-temperature-7c

HOPE THIS HELPED U

THANK U

MARK ME BRAINLY PLSS

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