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| 1. |
`5.7 g` of bleaching powder was suspended in `500 mL` of water. `25 mL` of this suspension on treatment with `KI` and `HCl` liberated iodine which reacted with `24.35 mL "of" N//10Na_(2)S_(2)O_(3)`. Calculate `%` of available `Cl_(2)` in bleaching powder. |
| Answer» `%` of chlorine `=30.33%` | |