5.An object takes 15 s to reach the ground from aheight of 40 m on a p

1.	5.An object takes 15 s to reach the ground from aheight of 40 m on a planet. What is the value ofg on the planet?[2 M]برا
Answer» Answer: Time taken, t = 5 seconds Displacement, s = 5 metres Initial velocity, u = 0 metres/second Let the acceleration be a m/s2 . When the acceleration is constant, initial velocity, acceleration, time taken and displacement are related by a simple FORMULA: s=ut+(1/2)at2 THEREFORE, 5=(0)(5)+(1/2)(a)(52) a×(25/2)=5 a=5/(25/2) a=10/25 a=2/5 a=0.4 Therefore, the acceleration is 0.4m/s2 . This is the acceleration DUE to GRAVITY on that planet. Please note that you can't call ‘acceleration due to gravity’ as ‘gravity’. Gravity refers to gravitational force. Gravitational force (gravity) due to the planet on any mass ‘m’ (EXPRESSED in kilograms) = (0.4×m) newtons. A⚡K Explanation: it is example sum i think it help you

5.An object takes 15 s to reach the ground from aheight of 40 m on a planet. What is the value ofg on the planet?[2 M]برا

Answer»

Answer:

Time taken, t = 5 seconds

Displacement, s = 5 metres

Initial velocity, u = 0 metres/second

Let the acceleration be a m/s2 .

When the acceleration is constant, initial velocity, acceleration, time taken and displacement are related by a simple FORMULA:

s=ut+(1/2)at2

THEREFORE,

5=(0)(5)+(1/2)(a)(52)

a×(25/2)=5

a=5/(25/2)

a=10/25

a=2/5

a=0.4

Therefore, the acceleration is 0.4m/s2 .

This is the acceleration DUE to GRAVITY on that planet.

Please note that you can't call ‘acceleration due to gravity’ as ‘gravity’.

Gravity refers to gravitational force. Gravitational force (gravity) due to the planet on any mass ‘m’ (EXPRESSED in kilograms) = (0.4×m) newtons.

A⚡K

Explanation:

it is example sum i think it help you

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