5. Angle of a Sect6h's 60 . and HS91adǐus4cm tindlt aea and pustmetes – InterviewSolution

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5. Angle of a Sect6h's 60 . and HS91adǐus4cm tindlt aea and pustmetes?mele9

Answer»

Area= theeta/360* π r^2

= 60/360* 22/7* 14*14102.62 cm^2

Perimeteras 2π r consist = 360°1° will consist= 2πr/360now 60° will consist= 2πr/360*60= 2π*14/628π/16cm

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