1.

5 cos' 60 +4 see 30" -an 4sin' 30cos' 30

Answer»

.( 5 cos²60°+4 sec²30°-tan²45°) ÷ (sin²30° +cos²30°)

= {5*(1/2)^2+ 4 (√3/2)^2-(1)^2} ÷{ (1/2)^2+(√3/2)^2}

={ 5/4+4*(3/4)-1}÷ (1/4+3/4)

= 5/4-2 ÷ 1 = -3/2



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