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`5` different objects are to be distributed among `3` persons such that no two persons get the same number of objects. Number of ways this can be done is,A. `60`B. `90`C. `120`D. `150` |
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Answer» Correct Answer - B `(b)` Division of objects can be `(0,1,4)` or `(0,2,3)` So total number of distribution ways `=(5!)/(0!*1!*4!)xx3!+(5!)/(0!*2!*3!)xx3!` `=30+60=90` ways |
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