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5 g of an unknown hgas has pressure P at temperature TK in a vessel. On increasing the temperature by `50^(@)C`, 1g of the was given out to maintain the pressure P. What was the original temperature of the gas ? |
Answer» Initially, `T_(1)=T,P_(1)=P,V_(1)=V `(Volume of the vessel), `n_(1)=(5)/(M)`mole Finally, `T_(2)=(T+50)K, P_(2)=P, V_(2)=V, n_(2)=(5-1)/(M)=(4)/(M)` mole (Increase of `50^(@)C`=increase of 50 K because size of `1^(@)C`=1 K) Applying PV=nRT `n_(1)T_(1)=n_(2)T_(2)` `(5)/(M)xxT=(4)/(M)(T+50)" or "5T=4T+200" or T=200 K` |
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