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5 g of Zn reacts with (I) Excess of NaOH (II) Dilute HCl, then volume ratio of H2 gas evolved in (I) and (II) is (1) 2 : 1 (2) 1 : 2 (3) 1 : 1 (4) 3 : 1 |
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Answer» The answer is (3) 1 : 1 Zn + 2NaOH → Na2ZnO2 + H2 Zn + 2HCl →ZnCl2 + H2 According to stoichiometry in both the reactions, equal number of moles of H2 are evolved. |
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