1.

5. How manymoles of magnesium phosphate, Mg3 (PO)2 will contain 0.25 mole of oxygen atoms ?O A)1.25 x 10-2B) 2.5 x 10-2D) 3.125 x 10-2C) 0.02

Answer»

moles of O in 1 moles of Mg3(PO4)2 = 8

for 1 mole of O → 1/8 mol Mg3(PO4)2 O so, for 0.25 mol of O → 1/8*0.25 =1/32 = 0.03125

option D


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