| 1. |
5. If the zeros of the polynomial f(a) ax3+3bx2 +3cx +d are in A.P., pro2b3-3abc +ad-oA D find |
|
Answer» Roots of given polynomial is in AP let P- r , P, and P+ r are the roots of f( x) = ax³ + 3bx² + 3cx + d sum of roots = -coefficient of x²/coefficient of x³ P -r + P + P+ r = -( 3b/a) 3P = -( 3b/a) P = -b/a -----------(1) sum of products of two roots = ( P -r)×P + P×(P+r) + (P-r)(P+r) = coefficient of x/coefficient of x³ P² -Pr + P² +Pr + P² -r² = 3c/a 3P² - r² = 3c/a ------------------(2) again , products of all roots = -constant /co-efficient of x³ (P-r)×P× (P+r) = - d/a P³ - Pr² = -d/a ----------(3) now, equation (1) put in eqn (2) , 3(-b/a)² -r ² = (3c/a) r² = 3(b²/a²) -3(c/a) ----------(4) eqn (4) and (1) put in eqn(3) (-b/a)³ -(-b/a)( 3b²/a² -3c/a ) = -d/a -b³/a³ +b/a(3b²/a² -3c/a ) = -d/a -b³/a³ +3b³/a³ -3bc/a² = - d/a 2b³/a³ -3bc/a² = -d/a 2b³ -3abc = -da² 2b³ -3abc + a²d = 0 hence, proved thanks alot sir |
|