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Explanation:

Given :-

Radius of circle = 4 cm

Angle ∅ = 30⁰

To FIND :-

Area of MAJOR sector

Solution :-

We know that

\sf \: Area \: of \: sector \: = \dfrac{ \theta}{360} \TIMES \pi {r}^{2}Areaofsector=

360

θ

×πr

2

θ = Angle

Here,

Angle is 30⁰

So,

⟹ 30/360 × 22/7(4)²

⟹ 3/36 × 22/7 × 4 × 4

⟹ 1/12 × 22/7 × 16

⟹ 22/84 × 16

⟹ 4.19 cm

Now,

Area of major sector = Area of circle - Area of smaller circle

⟹ πr² - 4.19

⟹ 3.14 × (4)² - 4.19

⟹ 3.14 × 16 - 4.19

⟹ 50.24 - 4.19

⟹ Area of major sector ≈ 46.05 cm


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