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5 mL of N HCl, 20 mL of N/2 `H_(2)SO_(4)` and 30 mL of `N/3HNO_(3)` are mixed together and volume made to 1L. The normality of resulting solution isA. 0.45B. 0.025C. 0.9D. 0.05 |
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Answer» Normally equtaion is `N_(1)V_(1)+N_(2)V_(2)+N_(3)V_(3)=N_(4)(V_(1)+V_(2)+V_(3))` or `1xx5+20xx(1)/(2)+30xx(1)/(3)=N_(4)(5+20+30)` `(HCI) (H_(2)SO_(4)) (HNO_(3))` `therefore` Resulting normality `(N_(4))=(25)/(55)=0.45N`. |
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