5 moles of Ba(OH)_(2) are treated with excess of CO_(2). How much Ba(OH_(2) will be formed?

5 moles of Ba(OH)_(2) are treated with excess of CO_(2). How much Ba(O

1.	5 moles of Ba(OH)_(2) are treated with excess of CO_(2). How much Ba(OH_(2) will be formed?
Answer» <html><body><p>39.4 g<br/>197 g<br/>591 g<br/>985g<br/></p>Solution :d) `<a href="https://interviewquestions.tuteehub.com/tag/ba-389206" style="font-weight:bold;" target="_blank" title="Click to know more about BA">BA</a>(OH)_(2) + CO_(2) to BaCO_(3) + H_(2)O` <br/> `therefore` <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> moles of `Ba(OH)_(3)` = 5 moles of `BaCO_(3)` <br/> `therefore` <a href="https://interviewquestions.tuteehub.com/tag/mass-1088425" style="font-weight:bold;" target="_blank" title="Click to know more about MASS">MASS</a> of `BaCO_(3)` = Moles of BaCO_(3) <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> Molecular mass of `BaCO_(3)` = `5 xx 197) = 985 g</body></html>