1.

5,prove that (cotA-cosA)÷ cotA+cosa=cosecA-1÷cosecA+1

Answer»

(cotA -cosA)/(cotA + cosA) = (cosecA-1)/(cosecA+1)

(cotA -cosA)/(cotA + cosA)

((cosA/sinA)-cosA)/((cosA/sinA)-cosA) cotA=cosA/sinA

taking cosA common from numretor nd denominatr nd cancelling it we get

((1/sinA)-1)/((1/sinA)+1) since 1/sinA=cosecA

therfore

(cosecA-1)/(cosecA+1)



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