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5. The energy required to melt lg. ice is 33J. The number of quanta of radiation of frequency 4.67 x 10power13 sec-1 that must be absorbed to melt 10g ice is1) 1.065 x 10power222) 3.205 x 10power233) 9.076 x 10power24) NonePLEASE GIVE DETAILED ANSWER |
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Answer» Answer: Energy required to melt 1g ice =33J. Energy required to melt 10g ice =33×10=330J. Radiation frequency (ν)=4.67×10 13 s −1
As we know, the energy of radiation is GIVEN by: E=hν Here, H= Planck's constant =6.62×10 −34 J.s ∴E=6.62×10 −34 ×4.67×10 13
⇒E=3.09×10 −20 J ∴ No. of quanta required = 3.09×10 −20
330
=1.067×10
Hence, the correct option is (A). Explanation: hope it helps you....... |
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