5. The reduction potential of SCE at 25°C is 0.2415 volts, it indicates (a) Hg2C12(s) + 2e → 2Hgm) + 2 C1“(Sat)(b) 2Hgm + 2 Cl(Sat) → Hg2 Cl26) + 2e(c) HgCl2 + 2e →Hg. + 2Cl(Sat)(d) Hg++ + 2e → Hg()til Eis the algebraic sum of the singleI

5. The reduction potential of SCE at 25°C is 0.2415 volts, it indicat

1.	5. The reduction potential of SCE at 25°C is 0.2415 volts, it indicates (a) Hg2C12(s) + 2e → 2Hgm) + 2 C1“(Sat)(b) 2Hgm + 2 Cl(Sat) → Hg2 Cl26) + 2e(c) HgCl2 + 2e →Hg. + 2Cl(Sat)(d) Hg++ + 2e → Hg()til Eis the algebraic sum of the singleI
Answer» Two half REACTIONS OXIDATION: H 2 O+1/2H 2 ⟶H 3 O + +e − , E cell o=0 Reduction: H 2 O+e − ⟶1/2H 2 (g) +OH − , E cell o =−0.8277V n=1 logK = 0.059 NE cell 0= 0.059 1×(−0.8277) =15.972 ∴K C=9.88×10 −15 Explanation: