1.

5. The reduction potential of SCE at 25°C is 0.2415 volts, it indicates (a) Hg2C12(5) + 2e → 2Hgc + 2 CIS(Sat)(b) 2Hgo + 2 C1 (sat) -→ Hg2 C129) + 2e(c) HgCl2 + 2e → Hgo + 2C1(d) Hg+ + 2e → Hgo)(Sat)​

Answer» C EXPLANATION:i HOPE my ANSWER HELP to you


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