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5. While performing an experiment to determine the percentage of water absorbed by raisins,[0. the following data was obtained: Mass of water taken in the beaker \( =50 g \) Mass of raisins before soaking them in water \( =5 g \) Mass of raisins after soaking in water for 2 hours \( =8 g \). The percentage of water absorbed by raisins would be :a) \( \frac{(8-5) g}{8 g} \times 100 \)b) \( \frac{(8-5) g}{5 g} \times 100 \)c) \( \frac{(8-3) g}{8 g} \times 100 \)d) \( \frac{(8-5) g}{3 g} \times 100 \) |
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Answer» The answer is (b) The percentage of water absorbed by raisins is calculated by using the formula W2-W1/W1 x 100 where W2 is the weight of wet raisin and W1 is the weight of dry raisin. |
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