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`(5-x)/(3) =(y+3)/(-2) ,z=5 " and " (x-1)/(1)=(1-y)/(3)=(z-5)/(2)` Find the angle between the lines. |
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Answer» Correct Answer - `cos^(-1).((3)/(sqrt(182)))` Given lines in standard form are : `(x-5)/(-3) =(y+3)/(-2) +(z-5)/(0) " and " (x-1)/(1)=(y-1)/(-3) =(z-5)/(2)` |
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