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50 gm of `CaCO_(3)` is allowed to react with 68.6 gm of `H_(3)PO_(4)` then select the correct option(s): `3CaCO_(3) +2H_(3)PO_(4) rarr Ca_(3)(PO_(4))_(2)+3H_(2)O+3CO_(2)`A. 51.67 gm salt is formedB. Amount of unreacted reagent =35.93 gmC. `n_(Co_(2))` =0.5 molesD. 0.7 moles of `CO_(2)` is evoled

Answer» Correct Answer - A::B::C


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