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50 gof CaCo3 is allowed to react with 70gof H₃ PO4 Calculate :1. amount of Ca3(PO) 4 formed.2. amount of unreactedunreacted reagent |
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Answer» Explanation: Type your question... 11th Chemistry Some Basic Concepts of Chemistry Stoichiometry and STOICHIOMETRIC Calculations 50 g of { CaCO }_{ 3 } is... CHEMISTRY 50 g of CaCO 3
is allowed to react with 70 g of H 3
PO 4
. Calculate : (i) amount of Ca 3
(PO 4
) 2
formed (ii) amount of unreacted reagent December 26, 2019 avatar Jenny Sagani Share Save ANSWER 2:3:1 2H 3
PO 4
+3CaCO 3
⟶Ca 3
(PO 4
) 2
+3H 2
0+3CO 2
1mol=98g1mol=100g 70g50g = 7 5
mol= 2 1
mol For 2 1
molCaCo 3
,weneed 3 2
× 2 1
= 3 1
molH 3
PO 4
∴Ca 3
(PO 4
) 2
formed= 2 1
× 3 1
= 6 1
moles = 6 1
×310g =51.66g unreactedH 3
PO 4
= 7 5
− 3 1
= 21 8
moles = 21 8
×98=37.33g
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