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50 is divided into two parts such that the sum of their reciprocals is 1/ 12. Find the two parts. |
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Answer» Let the two parts be x and (50 - x). Then, 1 / x + 1 / (50 – x) = 1 / 12 => (50 – x + x) / x ( 50 – x) = 1 / 12 => x2 – 50x + 600 = 0 => (x – 30) ( x – 20) = 0 => x = 30 or x = 20. So, the parts are 30 and 20. |
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