1.

50 is divided into two parts such that the sum of their reciprocals is 1/ 12. Find the two parts.

Answer»

Let the two parts be x and (50 - x). 

Then, 1 / x + 1 / (50 – x) = 1 / 12 

=> (50 – x + x) / x ( 50 – x) = 1 / 12 

 => x2 – 50x + 600 = 0 

=> (x – 30) ( x – 20) = 0 

=> x = 30 or x = 20. 

So, the parts are 30 and 20.



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