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50 ml of 0.2 N H_(2) SO_(4) is mixed with 100 ml of 0.4 N KOH solution and 1.85 lit of distilled water is added . The pH of resulting solution is (log 1.5 = 0.176)

Answer» <html><body><p>`13.301`<br/>`0.699`<br/>`1.824`<br/>`12.176`</p><a href="https://interviewquestions.tuteehub.com/tag/answer-15557" style="font-weight:bold;" target="_blank" title="Click to know more about ANSWER">ANSWER</a> :D</body></html>


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