1.

50 persons were examined through X-ray and observations were noted as under:Diameter of heart (in mm) : 120,121,122,123,124Number of patients: 5,8,12,9,6,10Find:(i) The mean diameter of heart,(ii) The median diameter of heart.

Answer»
Diameter of heart
(in mm)(xi)
Number of patients
(Frequecy) (fi)
fixicumulative frequency
(C.F.)
12056005
121896813
12212146425
1239110734
124674440
12510125050
n = \(\sum\)f= 50\(\sum\)fixi = 6133

\(\therefore\) Mean = \(\frac{\sum f_ix_i}{\sum f_i}\) = \(\frac{6133}{50}\) = 122.66

\(\frac{n}2=\frac{50}2=25\)

\(\therefore\) l = 122, c = 13, f = 12, h = 1

Medium = l + \(\cfrac{\frac{n}2-c}{f}\times h\) 

 = 122 + \(\frac{25-13}{12}\times 1\) 

 = 122 + \(\frac{12}{12}\times1\) 

 = 122 + 1 = 123

Hence, medium diameter of heart is 123 mm



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