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500 g of water is heated from 30^(@)C to 60^(@)C. Ignoring the slight expansion of water, calculate the change in internal energy of the water? ("Specific heat of water "4184 J// kg K) . |
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Answer» Solution :When the water is heated from `30^(@)C to 60^(@)`C, there is only a slight changes in its volume. So we can treat this proces as isochoric. In an isochoric process the work done by the system is zero. The given heat supplied is used to incrase only the INTERNAL energy. `DeltaU = Q = ms_(v)DELTAT` The mass of water = 500 g = 0.5 kg The change in tenperature = 30K The heat `Q = 0.5 xx 4184 xx 30 = 62.76 kJ` |
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