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`500 mL` of a glucose solution contains `6.02 xx 10^(22)` molecules. The concentration of the solution is :A. `0.1 M`B. `1.0M`C. `0.2M`D. `2.0M` |
Answer» Correct Answer - C Moles of solute `= (6.02xx10^(22))/(N_(A)) = 0.1 mol` concentration of solution `= ("moles")/("vol")` `=(1xx1000)/(500) = 2` |
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