1.

`500 mL` of a glucose solution contains `6.02 xx 10^(22)` molecules. The concentration of the solution is :A. `0.1 M`B. `1.0M`C. `0.2M`D. `2.0M`

Answer» Correct Answer - C
Moles of solute
`= (6.02xx10^(22))/(N_(A)) = 0.1 mol`
concentration of solution
`= ("moles")/("vol")`
`=(1xx1000)/(500) = 2`


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