. 500 ml of nitrogen at 27° C are cooled to-5°C atthe same pressure.

1.	. 500 ml of nitrogen at 27° C are cooled to-5°C atthe same pressure. Calculate the new volume.
Answer» At same pressure , volume is directly proportional to temp. so V1/T1 = V2/T2.=> 500/(273+27) = (V2)/(273-5) => V2 = (500/300)(268) = 446.6 ml. we know,pv=nrtp1/p2= t1/t2500 (-5+273) = x * (27+273)500 * 268 = x * 300x = (500*268)/300x= 446.67ml

. 500 ml of nitrogen at 27° C are cooled to-5°C atthe same pressure. Calculate the new volume.

Answer»

At same pressure , volume is directly proportional to temp.

so V1/T1 = V2/T2.=> 500/(273+27) = (V2)/(273-5) => V2 = (500/300)*(268) = 446.6 ml.

we know,pv=nrtp1/p2= t1/t2500 * (-5+273) = x * (27+273)500 * 268 = x * 300x = (500*268)/300x= 446.67ml