1.

50g of saturated solution of NaCl at 30 Cevaporated to dryness and 13.2g of dryCI was obtained. Find the solubility oflat 30°C in water.

Answer»

Mass of water in solution = (50 – 13.2) = 36.8 g

Solubility of NaCl = Mass of NaCl/Mass of water × 100 = 13.2/36.8 × 100=35.86



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