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52 g of He contains(a) 4 x 6.022 x 10*23 atoms(b) 13 atoms(c) 13 x 6.022 x 10*23 atoms(d) 4 atoms. |
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Answer» Answer: (i) 52 moles of Ar The number of atoms PRESENT in 52 mol of Ar can be calculated as follows. 1 moles of Ar = 6.022×1023 atoms of Ar 52 moles of Ar = 52 X 6.022 x 1023 ∴ 52 moles of Ar = 3.13144 × 1025 (ii) 52 U of He The atomic mass of He is 4 amu. 52 u of He will contain 52/4 = 13 atoms (III) 52 g of He 1 mole of He = 4 g = 6.022 × 10²³ atoms of He 52 grams of He will contain = 52/4 = 13 moles Number of atoms in 13 moles of He = 13 × 6.022 × 1023atoms Number of atoms in 13 moles of He = 78.29× 1023 atoms 52 grams of He = 7.829 × 1024 atoms |
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