InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
52. Kc for 2 / H ₂ + 1 / 2 areN = NH.0.0266 and 0.0129 are respectively at350°C and 400°C.Calculate heat offormation of NH.. |
|
Answer» tion:∴△H=−12140cal As we KNOW, 2.303log[ K P 1 K P 2 ]= R △H [ T 1 T 2 T 2 −T 1 ] 2.303log[ 0.0266 0.0129 ]= 2 △H [ 673×623 673−623 ] ∴△H=12140cal=−12140cal |
|