540g of ice at 0°C is mixed with 540g of water at 80°C. The temperat

1.	540g of ice at 0°C is mixed with 540g of water at 80°C. The temperature of mixture is : (a) 40°C (b) 80°C (c) 0°C (d) less than 0°C
Answer» Correct option (c) 0°C Explanation: The amount of heat required to melt 540g of ice is given by = 540 × 80 = 43200 cal (latent heat of ice = 80 kcal ⁄ g) Now heat lost by 540 g of water form 80°C to 0°C. = 540 × 1 × (80° − 0°) = 43200 cal Therefore, all the ice must be melt and temperature of mixture is zero.

540g of ice at 0°C is mixed with 540g of water at 80°C. The temperature of mixture is : (a) 40°C (b) 80°C (c) 0°C (d) less than 0°C

Answer»

Correct option (c) 0°C

Explanation:

The amount of heat required to melt 540g of ice is given by

= 540 × 80 = 43200 cal

(latent heat of ice = 80 kcal ⁄ g)

Now heat lost by 540 g of water form 80°C to 0°C.

= 540 × 1 × (80° − 0°)

= 43200 cal

Therefore, all the ice must be melt and temperature of mixture is zero.

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540g of ice at 0°C is mixed with 540g of water at 80°C. The temperature of mixture is : (a) 40°C (b) 80°C (c) 0°C (d) less than 0°C

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