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56g of n2 reacts 9g of h2 in a closed vessel to form nh3. which reactant is left and how much |
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Answer» N 2 + 3H 2 → 2NH 3 2 4 0 2−x 4−3x 2x According to the QUESTION, 2x=2=>x=1 Hence at EQUILIBRIUM, NUMBER of moles of N 2 =2−x=2−1=1 number of moles of H 2 =4−3x=4−3=1 number of moles of NH 3 =2x=2 |
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