1.

56g of n2 reacts 9g of h2 in a closed vessel to form nh3. which reactant is left and how much​

Answer»

N  2 ​        +     3H  2 ​           →    2NH  3 ​    2                  4                        0 2−x         4−3x                    2x According to the QUESTION, 2x=2=>x=1 Hence at EQUILIBRIUM, NUMBER of moles of N  2 ​   =2−x=2−1=1 number of moles of H  2 ​   =4−3x=4−3=1 number of moles of NH  3 ​   =2x=2



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