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56g of n2 reacts with 9g of h2 in a closed bessel to form nh3. which reactant is left in excess and how much |
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Answer» tion:3H2+N2=NH3 n(H2)=m/M =9/2 4.5 moln(N2)=m/M 56/28 =2 MOL :. n(H2)/3 and n(N2)/1 4.5/3 and 2/1 1.5 and 2 :. N2 is an excess REAGENT since it has a higher coeficient RATIO.... |
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