InterviewSolution
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InterviewSolution
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58.5 g of NaCl and 180 g of glucose were separately dissolved in 1000 mL of water. Identify the correct statement regarding the elevation of boiling point (b.pt.) of the resulting solutionsA. NaCl solution will show higher elevation of b.pt.B. Glucose solution will show higher elevation of b.pt.C. Both the soltuions will show equal elevation of b.pt.D. The b.pt. of elevation will be shown by neither of the solutions |
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Answer» Correct Answer - A `Delta T_(b) = i K_(b) m` For water `rarr 1000 mL = 1000 g` Molality of `NaCl=(w//M.W.)/("W(solvent)")xx1000` `=(58.5//58.5)/(1000)xx1000=1m` Molality of glucose `=(180//180)/(1000)xx1000=1m` i for NaCl = 2, i for glucose = 1 `Delta T_(b)` for `NaCl gt Delta T_(b)` for glucose |
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