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58· The number of Cl- ions in 100 mL of0.001 M HCl solutionsne022 × 10'9A) 6.022 x 1023B) 6022 × 10206.022 × 1019D) 6.022 × 1024

Answer»

0.001M HCl of 100mL will have 0.001*0.1 moles = 10^-4 moles

1 mole of HCl contains 6*10^23 Cl- ions

Thus 10^-4 moles of will contain 6*10^19 number of Cl ions



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