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-(5y2 + 2y – 6) Is this correct? If not, correct the mistake. |
Answer» Taking -(5y2 + 2y – 6) = 5y2 + [(-)(+) 2y] + [(-) × (-)6] = -5y2 – 2y + 6 ≠ -5y2 – 2y + 6 ∴ Correct answer is -5y2 + 2y – 6 = -(5y2 + 2y + 6) |
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