InterviewSolution
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InterviewSolution
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6.02 x 1020 molecules ofurea are present in 100 mLofits solution. The concentration ofurea solution is(A) 0.02 M(C) 0.01 MM(B) 0.001 M(D) 0.1 M |
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Answer» Moles of urea = molecules/avogadro no = 6.02X10^20 / 6.022 X 10^23 = 10^-3 molesSo it will have 10^-2 mole in 1 litre of solutionbecause Molarity/concentration = mole / litre = 10^-3/1L = 10^-2M =0.01Mhence,opction(C) is correct |
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