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6.022 xx 10^(20) molecules of urea are present in 100 mL of its solution. The concentration of urea solution is : |
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Answer» 0.001 M `(6.022xx10^(20))/(6.022xx10^(23))=0.001` MOL Concentration of solution `=((10^(-3)"mol"))/(("0.1 L"))xx10^(-2)"molL"^(-1)=0.01 M`. |
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