1.

6.022 xx 10^(20) molecules of urea are present in 100 mL of its solution. The concentration of urea solution is :

Answer»

0.001 M
0.01 M
0.02 M
0.1 M

SOLUTION :No. of MOLES urea
`(6.022xx10^(20))/(6.022xx10^(23))=0.001` MOL
Concentration of solution
`=((10^(-3)"mol"))/(("0.1 L"))xx10^(-2)"molL"^(-1)=0.01 M`.


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