InterviewSolution
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InterviewSolution
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6.025 x 1020 molecules of acetic acid are present in500 ml of its solution. The concentration of solution is(1) 0.002 M(3) 0.012 M(2) 10.2 NM(4) 0.001 M |
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Answer» No of moles=(6.02×10^20÷(6.02×10^23))=10^-3now 500 ml contains 10^-3 mol.....so 1000ml contains=(10^-3÷500)×1000 mol=0.002molso the molarity or the concentration of the solution is 0.002 M.......☺️ |
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