1.

`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:A. (a)0.1 MB. (b)0.01 MC. (c )0.02 MD. (d)0.001 M

Answer» Correct Answer - B
`M=("Moles of urea")/("V in litre")`
`=(6.02xx10^(20)xx1000)/(6.023xx10^(23)xx100)=10^(-2) M`


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