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`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:A. (a)0.1 MB. (b)0.01 MC. (c )0.02 MD. (d)0.001 M |
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Answer» Correct Answer - B `M=("Moles of urea")/("V in litre")` `=(6.02xx10^(20)xx1000)/(6.023xx10^(23)xx100)=10^(-2) M` |
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