`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:A. `0.1 M`B. `0.001 M`C. `0.1 M`D. `0.02 M`

`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. Th

1.	`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:A. `0.1 M`B. `0.001 M`C. `0.1 M`D. `0.02 M`
Answer» Correct Answer - A Number of moles (urea) `= (6.02xx10^(20) "molecules")/(6.02xx10^(23) "molecules" mol^(-1))` `= 0.01 mol` Volume of soltuion in liters `= (100 mL)/(1000 mL L^(-1)) = 0.1L` Molarity `= ("Number of moles")/("Volume in liters") = (0.01 mol)/(0.1) = 0.01M`

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`6.02xx10^(20)` molecules of urea are present in `100 mL` solution. The concentration of urea solution is:A. `0.1 M`B. `0.001 M`C. `0.1 M`D. `0.02 M`

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