InterviewSolution
Saved Bookmarks
| 1. |
`6.0xx10^(20)` molecules of urea are present in 100 L of his solution. The concentration of urea solution isA. 0.001 MB. 0.1 MC. 0.02 MD. 0.01 M |
|
Answer» Correct Answer - D No. of moles of urea `= (6.02xx10^(20))/(6.02xx10^(23))=10^(-3)` mol `:. 10^(-3)` mol of urea are present in 100 mL `:.` Moles of urea present in 1L (1000 mL) `=10^(-3)xx10=10^(-2)` `:.` Molarity of solution `= 10^(-2) M = 0.01 M` |
|